在c语言中,运算符是一个符号,告诉编译器执行特定的数学或逻辑函数,c语言提供丰富的内置运算符,并提供以下类型的运算符 -
在本章中,我们将学习每个运算符的工作方式。打开visual studio 2017创建一个win32 console application 项目,名称为:c-operators 。
下表显示了c语言支持的所有算术运算符。假设变量a的值是10,变量b的值是20,那么 -
| 运算符 | 描述 | 示例 |
|---|---|---|
+ |
将两个操作数相加 | a + b = 30 |
- |
从第一个操作数减去第二个操作数 | a − b = -10 |
* |
将两个操作数相乘 | a * b = 200 |
/ |
将第一个操作数除以第二个操作数 | |
% |
模数运算符和整数除法后的余数。 | b % a = 0 |
++ |
递增运算符将整数值增加1。 |
a++ = 11 |
-- |
递减运算符将整数值减1。 | a-- = 9 |
创建一个源代码文件:arithmetic_operators.c,如下代码 -
#include <stdio.h>
void main() {
int a = 21;
int b = 10;
int c ;
c = a + b;
printf("line 1 - value of c is %d\n", c );
c = a - b;
printf("line 2 - value of c is %d\n", c );
c = a * b;
printf("line 3 - value of c is %d\n", c );
c = a / b;
printf("line 4 - value of c is %d\n", c );
c = a % b;
printf("line 5 - value of c is %d\n", c );
c = a++;
printf("line 6 - value of c is %d\n", c );
c = a--;
printf("line 7 - value of c is %d\n", c );
}
执行上面示例代码,得到以下结果 -
line 1 - value of c is 31
line 2 - value of c is 11
line 3 - value of c is 210
line 4 - value of c is 2
line 5 - value of c is 1
line 6 - value of c is 21
line 7 - value of c is 22
请按任意键继续. . .
下表显示了c语言支持的关系运算符。假设变量a=10,变量b=20,则 -
| 运算符 | 描述 | 示例 |
|---|---|---|
== |
检查两个操作数的值是否相等。 如果相等,则条件成立。 | (a == b)结果为false |
!= |
检查两个操作数的值是否相等。 如果值不相等,则条件成立。 | (a != b) 结果为true |
> |
检查左操作数的值是否大于右操作数的值。 如果是,则条件成立。 | (a > b) 结果为false |
< |
检查左操作数的值是否小于右操作数的值。 如果是,则条件成立。 | (a < b)结果为true |
>= |
检查左操作数的值是否大于等于右操作数的值。 如果是,则条件成立。 | (a >= b) 结果为false |
<= |
检查左操作数的值是否小于等于右操作数的值。 如果是,则条件成立。 | (a <= b)结果为true |
创建一个源代码文件:relational_operators.c,如下代码 -
#include <stdio.h>
main() {
int a = 21;
int b = 10;
int c ;
if( a == b ) {
printf("line 1 - a is equal to b\n" );
}
else {
printf("line 1 - a is not equal to b\n" );
}
if ( a < b ) {
printf("line 2 - a is less than b\n" );
}
else {
printf("line 2 - a is not less than b\n" );
}
if ( a > b ) {
printf("line 3 - a is greater than b\n" );
}
else {
printf("line 3 - a is not greater than b\n" );
}
/* lets change value of a and b */
a = 5;
b = 20;
if ( a <= b ) {
printf("line 4 - a is either less than or equal to b\n" );
}
if ( b >= a ) {
printf("line 5 - b is either greater than or equal to b\n" );
}
}
执行上面示例代码,得到以下结果 -
line 1 - a is not equal to b
line 2 - a is not less than b
line 3 - a is greater than b
line 4 - a is either less than or equal to b
line 5 - b is either greater than or equal to b
请按任意键继续. . .
下表显示了c语言支持的所有逻辑运算符。 假设变量a=1,变量b=0,则 -
| 运算符 | 描述 | 示例 |
|---|---|---|
&& |
逻辑与运算符。 如果两个操作数都不为零,则条件成立。 | (a && b)结果为false |
![]() |
称为逻辑或运算符。如果两个操作数中的任何一个非零,则条件成立。 | (a b)结果为true |
! |
称为逻辑非运算符,它用于反转其操作数的逻辑状态。如果条件为真,则逻辑not运算符将使其结果为false。 |
示例:创建一个源文件:logical_operators.c,代码如下 -
#include <stdio.h>
main() {
int a = 5;
int b = 20;
int c ;
if ( a && b ) {
printf("line 1 - condition is true\n" );
}
if ( a || b ) {
printf("line 2 - condition is true\n" );
}
/* lets change the value of a and b */
a = 0;
b = 10;
if ( a && b ) {
printf("line 3 - condition is true\n" );
}
else {
printf("line 3 - condition is not true\n" );
}
if ( !(a && b) ) {
printf("line 4 - condition is true\n" );
}
}
执行上面代码,得到以下结果 -
line 1 - condition is true
line 2 - condition is true
line 3 - condition is not true
line 4 - condition is true
按位运算符对位进行操作,并执行逐位运算。 &,|和^的真值表如下 -
| p | q | p & q | p/q | p ^ q |
|---|---|---|---|---|
| 0 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 1 | 1 |
| 1 | 1 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 | 1 |
假设a = 60,b = 13,二进制格式如下:
a = 0011 1100
b = 0000 1101
-----------------
a&b = 0000 1100
a|b = 0011 1101
a^b = 0011 0001
~a = 1100 0011
下表列出了c语言支持的按位运算符。假设变量a=60,变量b=13,则 -
| 运算符 | 描述 | 示例 |
|---|---|---|
& |
如果二进制and运算符存在于两个操作数中,则二进制and运算符将对结果复制一位。 | (a&b)= 12,即0000 1100 |
![]() |
二进制or运算符如果存在于任一操作数中,则复制一位。 | (a b) = 61, 即 0011 1101 |
^ |
二进制xor操作符复制该位,如果它设置在一个操作数中,而不是两者。 | (a ^ b) = 49, 即, 0011 0001 |
~ |
二进制补码运算符是一元的,具有“翻转”位的作用。 | (~a)= -61,即 1100 0011的补码形式。 |
<< |
二进制左移操作符,左操作数值左移由右操作数指定的位数。 | a << 2 = 240 即, 1111 0000 |
>> |
二进制右移操作符,左操作数值被右操作数指定的位移动。 | a >> 2 = 15 即,0000 1111 |
示例: 创建一个源代码文件:bitwise_operators.c,代码如下所示 -
#include <stdio.h>
main() {
unsigned int a = 60; /* 60 = 0011 1100 */
unsigned int b = 13; /* 13 = 0000 1101 */
int c = 0;
c = a & b; /* 12 = 0000 1100 */
printf("line 1 - value of c is %d\n", c );
c = a | b; /* 61 = 0011 1101 */
printf("line 2 - value of c is %d\n", c );
c = a ^ b; /* 49 = 0011 0001 */
printf("line 3 - value of c is %d\n", c );
c = ~a; /*-61 = 1100 0011 */
printf("line 4 - value of c is %d\n", c );
c = a << 2; /* 240 = 1111 0000 */
printf("line 5 - value of c is %d\n", c );
c = a >> 2; /* 15 = 0000 1111 */
printf("line 6 - value of c is %d\n", c );
}
执行上面代码,得到以下结果 -
line 1 - value of c is 12
line 2 - value of c is 61
line 3 - value of c is 49
line 4 - value of c is -61
line 5 - value of c is 240
line 6 - value of c is 15
请按任意键继续. . .
下表列出了c语言支持的赋值运算符 -
| 运算符 | 描述 | 示例 |
|---|---|---|
= |
简单赋值运算符,将右侧操作数的值分配给左侧操作数 | c = a + b,将a + b的值分配给c |
+= |
相加与赋值运算符。它将右操作数添加到左操作数,并将结果分配给左操作数。 | c + = a等价于c = c + a |
-= |
相减与赋值运算符。它从左操作数中减去右操作数,并将结果分配给左操作数。 | c -= a等价于 c = c - a |
*= |
乘以与赋值运算符。它将右操作数与左操作数相乘,并将结果分配给左操作数。 | c * = a等价于c = c * a |
/= |
除以与赋值运算符。它将左操作数与右操作数分开,并将结果分配给左操作数。 | c /= a等价于c = c / a |
%= |
模数与赋值运算符。它需要使用两个操作数的模数,并将结果分配给左操作数。 | c %= a等价于c = c % a |
<<= |
左移与赋值运算符 | c <<= 2等价于c = c << 2 |
>>= |
右移与赋值运算符 | c >> = 2等价于c = c >> 2 |
&= |
按位与赋值运算符 | c &= 2等价于c = c & 2 |
^= |
按位异或运算符和赋值运算符。 | c ^= 2等价于c = c ^ 2 |
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按位包含or和赋值运算符。 | ![]() |
示例: 创建一个源文件:assignment_operators.c ,其代码如下 -
#include <stdio.h>
void main() {
int a = 21;
int c ;
c = a;
printf("line 1 - = operator example, value of c = %d\n", c );
c += a;
printf("line 2 - += operator example, value of c = %d\n", c );
c -= a;
printf("line 3 - -= operator example, value of c = %d\n", c );
c *= a;
printf("line 4 - *= operator example, value of c = %d\n", c );
c /= a;
printf("line 5 - /= operator example, value of c = %d\n", c );
c = 200;
c %= a;
printf("line 6 - %= operator example, value of c = %d\n", c );
c <<= 2;
printf("line 7 - <<= operator example, value of c = %d\n", c );
c >>= 2;
printf("line 8 - >>= operator example, value of c = %d\n", c );
c &= 2;
printf("line 9 - &= operator example, value of c = %d\n", c );
c ^= 2;
printf("line 10 - ^= operator example, value of c = %d\n", c );
c |= 2;
printf("line 11 - |= operator example, value of c = %d\n", c );
}
执行上面代码,得到以下结果 -
line 1 - = operator example, value of c = 21
line 2 - += operator example, value of c = 42
line 3 - -= operator example, value of c = 21
line 4 - *= operator example, value of c = 441
line 5 - /= operator example, value of c = 21
line 6 - = operator example, value of c = 11
line 7 - <<= operator example, value of c = 44
line 8 - >>= operator example, value of c = 11
line 9 - &= operator example, value of c = 2
line 10 - ^= operator example, value of c = 0
line 11 - |= operator example, value of c = 2
请按任意键继续. . .
除了上面讨论的运算符,还有一些其他重要的运算符,包括sizeof和? :也被c语言所支持。
| 运算符 | 描述 | 示例 |
|---|---|---|
sizeof() |
返回变量的大小 | sizeof(a),其中a为整数,将返回4。 |
& |
返回变量的地址 | &a; 返回变量的实际地址。 |
* |
指向变量的指针 | *a; |
? : |
条件表达式 | 如果条件是真的? 那么返回值x:否则返回y |
示例: 创建一个源文件:sizeof_operator.c ,其代码如下 -
#include <stdio.h>
void main() {
int a = 4;
short b;
double c;
int* ptr;
/* example of sizeof operator */
printf("line 1 - size of variable a = %d\n", sizeof(a));
printf("line 2 - size of variable b = %d\n", sizeof(b));
printf("line 3 - size of variable c= %d\n", sizeof(c));
/* example of & and * operators */
ptr = &a; /* 'ptr' now contains the address of 'a'*/
printf("value of a is %d\n", a);
printf("*ptr is %d.\n", *ptr);
/* example of ternary operator */
a = 10;
b = (a == 1) ? 20 : 30;
printf("value of b is %d\n", b);
b = (a == 10) ? 20 : 30;
printf("value of b is %d\n", b);
}
执行上面代码,得到以下结果 -
line 1 - size of variable a = 4
line 2 - size of variable b = 2
line 3 - size of variable c= 8
value of a is 4
*ptr is 4.
value of b is 30
value of b is 20
请按任意键继续. . .
运算符优先级决定表达式中术语的分组,并决定如何评估计算表达式。 某些运算符的优先级高于其他运营商; 例如,乘法运算符的优先级高于加法运算符,则先要执行乘法运算符的运算。
让我们通过下面的例子了解优先级:
int value = 10 + 20 * 10;
value变量计算结果为:210,因为*(乘法运算符)的优先级比+(加法运算符)高,所以在+(加法运算符)之前进行求值。
c语言运算符的优先级和关联性如下:
| 分类 | 运算符 | 关联性 |
|---|---|---|
| 后缀 | () [] -> . ++ - - |
左到右 |
| 一元 | + - ! ~ ++ - - (type)* & sizeof |
右到左 |
| 乘法 | * / % |
左到右 |
| 加法 | + - |
左到右 |
| 位移 | << >> |
左到右 |
| 关系 | < <= > >= |
左到右 |
| 等于 | == != |
左到右 |
| 按位与 | & |
左到右 |
| 位异或 | ^ |
左到右 |
| 按位或 | / |
左到右 |
| 逻辑与 | && |
左到右 |
| 逻辑或 | // |
左到右 |
| 条件 | ?: |
右到左 |
| 赋值 | = += -= *= /= %=>>= <<= &= ^= /= |
右到左 |
| 逗号 | , |
左到右 |
示例: 创建一个源文件:operators_precedence.c ,其代码如下 -
#include <stdio.h>
void main() {
int a = 20;
int b = 10;
int c = 15;
int d = 5;
int e;
e = (a + b) * c / d; // ( 30 * 15 ) / 5
printf("value of (a + b) * c / d is : %d\n", e);
e = ((a + b) * c) / d; // (30 * 15 ) / 5
printf("value of ((a + b) * c) / d is : %d\n", e);
e = (a + b) * (c / d); // (30) * (15/5)
printf("value of (a + b) * (c / d) is : %d\n", e);
e = a + (b * c) / d; // 20 + (150/5)
printf("value of a + (b * c) / d is : %d\n", e);
return 0;
}
执行上面代码,得到以下结果 -
value of (a + b) * c / d is : 90
value of ((a + b) * c) / d is : 90
value of (a + b) * (c / d) is : 90
value of a + (b * c) / d is : 50
请按任意键继续. . .
